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The ratio of amplitude of magnetic field...

The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacumm is equal to

A

The speed of light in vacuum

B

Reciprocal of speed of light in vacuum

C

The ratio of magnetic permeability to the electric susceptibility of vacuum

D

Unity

Text Solution

Verified by Experts

The correct Answer is:
B

`U= (1)/(2)epsilonE^(2)= (1)/(2)(B^(2))/(mu_(0))`
`epsilon_(0)mu_(0)= (B^(2))/(E^(2))implies(B)/(E) =sqrt(epsilon_(0)mu_(0))= (1)/(c)`
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