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A radiation of energy 'E'falls normally ...

A radiation of energy 'E'falls normally on a perfectly reflecting surface. The momentum transferred to the surface is (C = Velocity of light)

A

`(2E)/(c)`

B

`(2E)/(c^(2))`

C

`(E)/(c^(2))`

D

`(E)/(c)`

Text Solution

Verified by Experts

The correct Answer is:
A

Fore perfectly reflecing surface
`P= (2U)/(c)=(2E)/(c)`
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