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Statement I: In Young's double-slit expe...

Statement I: In Young's double-slit experiment, the two slits are at distance d apart. Interference pattern is observed on a screen at distance D from the slits. At a point on the screen which is directly opposite to one of the slits, a dark fringe is observed. Then, the wavelength of wave is proportional to the squar of distance between two slits.
Statement II: For a dark fringe, intensity is zero

A

If both assertion and reason are true and the reason is the correct explanation of the assertion

B

If both assertion and reason are true but reason is not the correct explanation of the assertion

C

If assertion is true but reason is false.

D

If the assertion and reason both are false

Text Solution

Verified by Experts

The correct Answer is:
B


When dark fringe is obtained at the point opposite to one of the slits then
`S_(1)P= D` and `S_(2)P= sqrt(D^(2)+ d^(2))= D(1+(d^(2))/(D^(2)))^(1//2)= D(1+ (d^(2))/(2D^(2)))`
Path difference = `S_(2)P- S_(1)P`
`= D(1+ (d^(2))/(2D^(2)))-D=(d^(2))/(2D)= (lambda)/(2)`
`lambda= (d^(2))/(D) implies lambda prop d^(2)`
Now, intensity of a dark fringe is zero.
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