Arrange the following steps of construction of a triangle PQR in which PQ = 5 cm, QR + RP = 8 cm and `angleQ = 60^@` in correct sequence.
Steps of construction :
Step 1 : Draw `anglePQX = 60^@`
Step 2 : Draw the perpendicular bisector of PY meeting QY at R.
Step 3 : Join PY.
Step 4 : Join PR.
Step 5 : Along `vecQX` , cut off line segment QY = QR + RP= 8 cm.
Step 6 : Draw PQ = 5 cm.
Hence, `DeltaPQR` is the required triangle.

Options

A. ` 6, 1, 3, 2, 4, 5`
B. `6, 5, 1, 3, 2, 4`
C. `6, 1, 5, 3, 4, 2`
D. `6, 1, 5, 3, 2, 4 `

Answer

To construct triangle PQR with the given conditions, we will follow these steps in the correct sequence:

### Step-by-Step Solution:

1. **Step 6: Draw PQ = 5 cm.**
- Start by drawing a line segment PQ that measures 5 cm.

2. **Step 1: Draw angle PQX = 60°.**
- At point Q, use a protractor to construct an angle of 60° with line segment PQ. Extend this line to create ray QX.

3. **Step 5: Along vector QX, cut off line segment QY = QR + RP = 8 cm.**
- Measure 8 cm along ray QX and mark point Y, so that QY = 8 cm.

4. **Step 3: Join PY.**
- Connect points P and Y with a straight line.

5. **Step 2: Draw the perpendicular bisector of PY meeting QY at R.**
- Find the midpoint of segment PY and draw a perpendicular bisector. This line will intersect line QY at point R.

6. **Step 4: Join PR.**
- Finally, connect points P and R with a straight line.

### Conclusion:
- The triangle PQR is now constructed according to the given conditions.