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C++ MCQ CLASS 12

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From a frequency distribution, c = 3, l = 65 . 5 f = 42, m = 23, N = 102 then median is (l = lower limit of the median class, m= cumulative frequency of the class preceeding the median class, N = total frequency, f = frequency of the median class, c = width of the median class)

In Fig. , A D=4c m , B D=3c m and C B=12 c m , find cottheta . (a) (12)/5 (b) 5/(12) (c) (13)/(12) (d) (12)/(13) (

In Figure, A D=4c m , B D=3c m and C B=12 c m , find cottheta . (a) (12)/5 (b) 5/(12) (c) (13)/(12) (d) (12)/(13)

If \ ^n C_(12)=\ \ ^n C_8 then = a. 20 b. 12 c. 6 d. 30

Write the median class of the following distribution: Classes: 0-10 10-20 20-30 30-40 40-50 50-60 60-70 Frequency: 4 4 8 10 12 8 4

Solve for a, b and c, a + b = 10, b + c = 12 and a + c = 16 .

If 1/a :1/b :1/c=3:4:5, then a : b : c (a) 5:4:3 (b) 20 : 15 : 12 (c) 9: 12 : 15 (d) 12 : 15 : 20

In a frequency distribution, the mid-value of a class is 15 and the class intervals is 4. The lower limit of the class is 10 (b) 12 (c) 13 (d) 14