A `2.0 cm` tall object is placed `15 cm` in front of concave mirrorr of focal length `10 cm`. The size and nature of the image will be

Options

A. 4 cm, real
B. 4 cm, virtual
C. 1.0 cm, real
D. None of these

Answer

A

Explanation

`h_(O) = 2 cm , u = -15 cm, ` f = -10 cm
Mirror formula, `(1)/(v) + (1)/(u) = (1)/(f)`
`rArr " "(1)/(v) = (1)/(f) - (1)/(u) = - (1)/(10) + (1)/(15) rArr v = - 30` cm
Image is real.
Magnification (m) ` = (-v)/(u) = (h_(1))/(h_(O)) rArr (- (-30))/(- 15) = (h_(l))/(h_(O))`
`" " rArr h_(l) = - 4 `cm