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The ratio of angle of minimum deviation ...

The ratio of angle of minimum deviation of a prism in air and when dipped in water will be `(mu_(g)=3//2 and mu_(w)=4//3)`

A

`1//8`

B

`1//2`

C

`3//4`

D

`1//4`

Text Solution

Verified by Experts

The correct Answer is:
D
`delta_(m) = A(n_(21) - 1)`
`rArr (delta_(m))/(delta_(a)) = (n_(gw) - 1)/( n_(ga - 1) = ((9)/(8) - 1)/((3)/(2) - 1) = (1)/(4) `.
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