A parallel beam of monochromatic light is incident at one surface of a equilateral prism. Angle of incidence is `55^(@)` and angle of emergence is `46^(@)`. The angle of minimum deviation will be

Options

A. `30^(@)`
B. `60^(@)`
C. `50^(@)`
D. `100^(@)`

Answer

A

Explanation

Since, deviation `delta = i+ e - A `
`rArr " " delta = 55^(@) + 46^(@) - 60^(@) = 41^(@)`
For minimum deviation i= e
`delta lt 41^(@). " as" delta_(m) lt delta `