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The light ray is incidence at angle of `60^(@)` on a prism of angle `45^(@)` . When the light ray falls on the other surface at `90^(@)` , the refractive index of the material of prism` mu` and the angle of devation `delta` are given by

A

n= `sqrt(2), delta = 30^(@)`

B

n= 1.5 , `delta = 15^(@)`

C

`n = (sqrt(3))/(2), delta = 30^(@)`

D

`n = sqrt((3)/(2)), delta = 15^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D

`e = 0 , r_(2) = 0 `
A = `r_(1) = 45^(@) `
n ` = (sin i)/(sin r) = (sin 60^(@))/(sin 45^(@)) = sqrt((3)/(2))`
`delta_(m) = i+ e - A = 60^(@) + 0^(@) - 45^(@) = 15^(@) `
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