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The far point of a myopia eye is at 40 c...

The far point of a myopia eye is at `40 cm`. For removing this defect, the power of lens required will be

A

40 D

B

`– 4 D`

C

`– 2.5 D`

D

0.25 D

Text Solution

Verified by Experts

The correct Answer is:
C
For myopic eye f = −(defected far point)
`f = -40 cm rArr P = (100)/(-40) = -2.5 `D.
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