When the object is self-luminous, the resolving power of a microscope is given by the expression

Options

A. `(2mu sin theta )/(1.22 lambda)`
B. `(mu sin theta )/(lambda)`
C. `(2mu cos theta )/(1.22 lambda )`
D. `(2 mu )/( lambda )`

Answer

A

Explanation

`d_(min) = (1.22 lambda )/(2 mu sin theta)`
and resolving power = `(2 mu sin theta)/(1.22 lambda)`.