The diameter of the objective of the telescope is `0.1` metre and wavelength of light is `6000 Å`. Its resolving power would be approximately

Options

A. `7.32 xx 10^(-6)` rad
B. `1.36 xx 10^(6)` rad
C. `7.32 xx 10^(-5)` rad
D. `1.36 xx 10^(5)` rad

Answer

D

Explanation

Resoving power = `(d)/(1.22 lambda) = (0.1)/(1.22 xx 6000 xx 10^(-10)) `
`1.36 xx 10^(5) ` radian.