Two point white dots are 1mm apart on a black paper. They are viewed by eye of pupil diameter 3mm. Approximately, what is the maximum distance at which these dits can be resolved by the eye? [Take wavelelngth of light =500nm]

Options

A. 6 m
B. 3 m
C. 5 m
D. 1

Answer

C

Explanation

`Delta theta = (x)/(d) = (1.22 lambda)/(a)`
`rArr d = (1xx 10^(-3) xx 3 xx 10^(-3))/(1.22 xx 500 xx 10^(-9))` = 4.91 = 5m .