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For the angle of minimum deviation of a...

For the angle of minimum deviation of a prism to be equal to its refracting angle, the prism must be made of a material whose refractive index

A

Lies between `sqrt(2)` and 1

B

Lies between 2 and `sqrt(2)`

C

Is less than I

D

Is greater than 2

Text Solution

Verified by Experts

The correct Answer is:
B

n `= (sin ( (A + delta_(m))/(2)) )/(sin A//2) = (sin ((A + A)/(2)) )/(sin A//2) = (2 sin A//2 cos A// 2 )/(sin A // 2 )`
n = 2 cos `(A)/(2)`
`(n)_(min) = 2 cos (90)/(2) sqrt(2), " " (n)_(max) = 2 cos 0^(@) = 2. `
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