V

The box in the circuit below has two inputs marked v + " and"v - and a single output marked V_o . The output obeys + 10 V if v + gt v- V_0 = -10 V if v + lt v- The output V_0 of this circuit a long time after is switched on is best represented by

Two batteries V_(1) and V_(2) are connected to three resistors as shown below. If V_(1) = 2V and V_(2) = 0 V, the current I = 3 mA. If V_(1) = 0 V and V_(2) = 4V, the current I = 4mA. Now, if V_(1) = 10 V and V_(2) = 10 V, the current I will be-

A series L-C-R circuit is connected across a variable frequency source of emf. V_(L), V_(C), V_(R) are instantaneous voltage drops across inductor capacitor and resistor and V is instantaneous voltage across the circuit. {:(" Column I",," Column II"),((A) |V|,,(p) "Can be greater than zero"),((B) |V|-|V_(L)|,,(q) "Can be less than zero"),((C) |V|-|V_(C)|,,(r)"Can be equal to zero"),((D) |V|-|V_(R)|,,):}

Figure shows a series LCR cicuit connected to a variable voltage source V=10sin(omegat+pi//4), x_(L)=10Omega, X_(c)=6Omega, R=3Omega Calculate Z, i_(0), i_(rms), V_(rms), V_(LO), V_(CO), V_(RO), beta, V_(LRms), V_(CRms), V_(Rms), i(t), V_(L)(t), V_(e(t)), " and " V_(R(t))

For a gas sample with N_(0) number of molecules, function N(V) is given by: N(V) = (dN)/(dV) = ((3N_(0))/(V_(0)^(3)))V^(2) for 0 lt V lt V_(0) and N(V) = 0 for V gt V_(0) . Where dN is number of molecules in speed range V to V+ dV . The rms speed of the molecules is: