Let f(x) = 4cos sqrt(x^2-pi^2/9). Then...

Let `f(x) = 4cos sqrt(x^2-pi^2/9)`. Then

A

the domain of `f` is `[pi/3,+oo)`

B

the range of `f` is `[-1,1]`

C

the domain of `f` is `(-oo,-pi/3]uu[pi/3,+oo)`

D

the range of `f` is [-4,4]

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