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If the root of the equation Ax^2 - Bx + ...

If the root of the equation `Ax^2 - Bx + C = 0` are -1 and 1, then which one of the following is correct?

A

A and Care both zero

B

A and B are both positive

C

A and C are both negative

D

A and C are of opposite sign

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The correct Answer is:
To solve the problem, we need to analyze the quadratic equation \( Ax^2 - Bx + C = 0 \) given that its roots are -1 and 1. ### Step-by-step Solution: 1. **Use Vieta's Formulas**: According to Vieta's formulas, for a quadratic equation \( Ax^2 + Bx + C = 0 \), if the roots are \( r_1 \) and \( r_2 \), then: - The sum of the roots \( r_1 + r_2 = -\frac{B}{A} \) - The product of the roots \( r_1 \cdot r_2 = \frac{C}{A} \) 2. **Calculate the Sum of the Roots**: - Here, the roots are -1 and 1. - The sum of the roots is: \[ -1 + 1 = 0 \] - According to Vieta's, we have: \[ -\frac{B}{A} = 0 \implies B = 0 \] 3. **Calculate the Product of the Roots**: - The product of the roots is: \[ (-1) \cdot 1 = -1 \] - According to Vieta's, we have: \[ \frac{C}{A} = -1 \implies C = -A \] 4. **Conclusion**: - From the calculations, we found that \( B = 0 \) and \( C = -A \). - This means that \( A \) and \( C \) are of opposite signs (if \( A \) is positive, \( C \) is negative, and vice versa). ### Final Result: The correct conclusion is that \( A \) and \( C \) are of opposite signs.
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OSWAL PUBLICATION-QUADRATIC EQUATIONS-Multiple Choice Question
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