Electric field intensity due to a hollow hemispherical charged shell.

STATEMENT-1 : Inside an isolated hollow spherical shell of charge, electrostatic potential is constant everywhere and STATEMENT-2 : Electric field inside a hollow spherical shell of charge is always zero.

Intensity of gravitational field inside the hollow spherical shell is

Electric field intensity (E) due to an electric dipole varies with distance (r ) from the point of the center of dipole as :

Derive an expression for electric field intensity at a point due to point charge.

The electric field intensity at the center of a uniformly charged hemispherical shell is E_(0) . Now two portions of the hemisphere are cut from either side, and the remaining portion is shown in fig. If alpha=beta=pi//3 , then the electric field intesity at the center due to the remaining portion is

Electric field at the centre of uniformly charge hemispherical shell of surface charge density sigma is (sigma)/(n epsi_(0)) then find the value of n .

Electric field intensity at a point B due to a point charge Q kept at point A is 24 NC^(-1) , and electric potential at B due to the same charge is 12 JC^(-1) . Calculate the distance AB and magnitude of charge.

Using Gauss' law deduce the expression for the electric field due to a uniformly charged sperical conducting shell of radius R at a point (i) outside and (ii) inside the shell. Plot a graph showing variation of electric field as a function of r gt R and r lt R . (r being the distance from the centre of the shell)

Electric field intensity at a point due to an infinite sheet of charge having surface charge density sigma is E .If sheet were conducting electric intensity would be

State Gauss's theorem in electrostatics. Apply this theorem to derive an expression for electric field intensity at a point outside a uniformly charged thin spherical shell.