Electric field intensity due to finite linear charge density..

A charge Q is placed at the centre of a square If electric field intensity due to the charge at the corners of the square is E_(1) and the intensity at the mid point of the sidde of square is E_(2) then the ratio of (E_(1))/(E_(2)) will be

An uncharged metallic solid sphere of radius R is placed at a distance 2R from point charge Q as shown in figure. The electric field intensity due to induced charge at centre of sphere is

Derive an expression for electric field intensity at a point due to point charge.

Find out electric field intensity due to uniformly charged solid non-conducting sphere of volume charge density rho and radius R at following points : (i) At a distance r from surface of sphere (inside) (ii) At a distance r from the surface of sphere (outside)

Electric field intensity at a point due to an infinite sheet of charge having surface charge density sigma is E .If sheet were conducting electric intensity would be

Electric field intensity at a point B due to a point charge Q kept at point A is 24 NC^(-1) , and electric potential at B due to the same charge is 12 JC^(-1) . Calculate the distance AB and magnitude of charge.

A point charge of 100mu C is placed at 3 hat i+4 hat j m . Find the electric field intensity due to this charges at a point located at 9 hat i+12 hat j m .

Find the electric field due to an infinitely long cylindrical charge distribution of radius R and having linear charge density lambda at a distance half of the radius from its axis.

Electric field intensity (E) due to an electric dipole varies with distance (r ) from the point of the center of dipole as :

What is the electric field intensity at any point on the axis of a charged rod of length 'L' and linear charge density lambda ? The point is separated from the nearer end by a.