Electrostatic: Electric field intensity due to a charged ring.

A charge Q is placed at the centre of a square If electric field intensity due to the charge at the corners of the square is E_(1) and the intensity at the mid point of the sidde of square is E_(2) then the ratio of (E_(1))/(E_(2)) will be

Derive an expression for electric field intensity at a point due to point charge.

An uncharged metallic solid sphere of radius R is placed at a distance 2R from point charge Q as shown in figure. The electric field intensity due to induced charge at centre of sphere is

The SI unit of electric field intensity is

Electric field intensity at a point B due to a point charge Q kept at point A is 24 NC^(-1) , and electric potential at B due to the same charge is 12 JC^(-1) . Calculate the distance AB and magnitude of charge.

A point charge of 100mu C is placed at 3 hat i+4 hat j m . Find the electric field intensity due to this charges at a point located at 9 hat i+12 hat j m .

The maximum electric field intensity on the axis of a uniformly charged ring of charge q and radius R will be

Electric field intensity (E) due to an electric dipole varies with distance (r ) from the point of the center of dipole as :

Three equal charges, each +q are placed on the corners of an equilatreal triangel . The electric field intensity at the centroid of the triangle is

Electric Field due to Dipole