Home
Class 12
MATHS
The side AB of Delta ABC is fixed and is...

The side AB of `Delta ABC` is fixed and is of length 2a unit. The vertex moves in the plane such that the vertical angle is always constant and is `alpha`. Let x-axis be along AB and the origin be at A. Then the locus of the vertex is

A

`x^(2) + y^(2) + 2ax sin alpha + a^(2) cos alpha= 0`

B

`x^(2) + y^(2)- 2ax- 2ay cot alpha= 0`

C

`x^(2) + y^(2) - 2ax cos alpha - a^(2) = 0`

D

`x^(2) + y^(2) - ax sin alpha- ay cos alpha = 0`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

The base of a triangle lies along x= 1and is of length 1. The area of triangle is 1. The locus of vertex is

The base of a triangle lies along x=5 and is of length 1 .The area of triangle is 1 . The locus of vertex is

Base BC of triangle ABC is fixed and opposite vertex A moves in such a way that tan.(B)/(2)tan.(C)/(2) is constant. Prove that locus of vertex A is ellipse.

A and B are fixed points such that AB=2a .The vertex C of Delta ABC such that cot A+cot B= constant.Then locus of C is

Let the base of a triangle lie along the line x = a and be of length 2a. The area of this triangles is a^(2) , if the vertex lies on the line

Let the base of a triangle lie along the line x=a and be of length a. The area of this triangle is a2, if the vertex lies on the line

The base AB of a triangle is fixed and its vertex C moves such that sin A =k sin B (kne1) . Show that the locus of C is a circle whose centre lies on the line AB and whose radius is equal to (ak)/((1-k^2)) , a being the length of the base AB.