In an AP , if `a_2 = 26 and a_(15) =-26 `, then write the AP.

If a_(1), a_(2), a_(3) ,... are in AP such that a_(1) + a_(7) + a_(16) = 40 , then the sum of the first 15 terms of this AP is

If a_(n) be the term of an A.P. and if a_(7)=15 , then the value of the common difference that could makes a_(2)a_(7)a_(11) greatest is:

If a_(1), a_(2), a_(3),........, a_(n) ,... are in A.P. such that a_(4) - a_(7) + a_(10) = m , then the sum of first 13 terms of this A.P., is:

If the third term of an A.P. is 12 and 10th term is 26, then its 20th term is :

Positive integers a_1, a_2, ........ form an A.P. If a_1, = 10 and a_(a_2), =100, then(A) common difference of A.P. is equal to 6. (B) The value of a_3, is equal to 20.(C) The value of a_22, is equal to 136. (D) The value of a_(a_3), is equal to 820.

nth term of an AP is a_(n). If a_(1)+a_(2)+a_(3)=102 and a_(1)=15, then find a_(10)

3rd term of an A.P. Is 12 and 10th term is 26, then its 20th term is :

In an AP, as a_(7)=9 and a_(1)*a_(2)*a_(7) an to as is least,then the common difference is:

If in an A.P. a_(7)=9 and if a_(1)a_(2)a_(7) is least, then common difference is _____

Let a_1, a_2, …, a_21 be an AP such that sum_(n=1)^20 1/(a_n a_(n+1)) = 4/9 . if the sum of this AP is 189, then a_6a_16 is equal to :