Factorization part 2 | R.K Bansal | ICSE | CBSE |

Factors affecting K_(c) is -

Consider the binomial expansion of R = (1 + 2x )^(n) = I = f , where I is the integral part of R and f is the fractional part of R , n in N . Also , the sum of coefficient of R is 2187. If kth term is having greatest coefficient , the sum of all possible value of k, is

A spring of length 'l' has spring constant 'k' is cut into two parts of length l_(1) and l_(2) . If their respective spring constahnt are K_(1) and k_(2) , then (K_(1))/(K_(2)) is:

A bomb of mass 4m explodes into two parts of mass ratio 1 : 3. If k be the kinetic energy of larger part then K.E. of small part

If an angle alpha be divided into two parts such that the ratio of tangents of the parts is K. If x be the difference between the two parts , then prove that sinx = (K-1)/(K+1) sin alpha .

For the reaction: CO(g) +H_(2)O(g) hArr CO_(2)(g) +H_(2)(g) (Delta_(r)H)_(300K) = - 41.2 kJ mol^(-1) (Delta_(r)H)_(1200K) =- 33.0 kJ mol^(-1) (Delta_(r)S)_(300K) = - 4.2 xx 10^(-2) kJ mol^(-1) (Delta_(r)S)_(1200K) =- 3.0 xx10^(-2) kJ mol^(-1) Predict the direction of spontaneity of the reaction at 300K and 1200K . also calculated log_(10)K_(p) at 300K and 1200K .

Two reactions R_(2) and R_(2) have identical pre - exponential factors. Activations enery of R_(1) exceeds that of R_(2) by 10 kJ mol_(-1) . If k_(1) and k_(2) are rate constants for rate constants for reactions R_(1) and R_(2) respectively at 300k , then In (k_(2)/k_(1)) is equal to (R=8.314 J mol^(-1)K^(-1))

Use the factor theorem to find the value of k for which (a+2b),w h e r ea ,b!=0 is a factor of a^4+32 b^4+a ^3 b(k+3)dot

If 24 is a factor of h and 28 is a factor of k, must 21 be a factor of hk?