A `5Omega` resistor -is connected across a hattery of 6 volts Calculate the energy that dissipated as heat in 10 s.

An inductor 20xx10^(-3) a capacitor 100(mu)F and a resistor 50 Omega are connected in series across a source of emf V=10 sin 314 t . Then the energy dissipated in the circuit in 20 mim is

A 50 Omega resistor a 120 muF capacitor and an inductor of inductance 0.2 H are connected in series across an AC source of 10 V , 50 Hz . Calculate the average power and energy dissipated in 500 s.

An ac source is connected across a resistance of 10 Omega The power dissipated in the resistor is 100W The rms valuse of the current and voltge are .

By evaluating int i^(2)Rdt ,show that when a capacitor is charged by connecting it to a battery through a resistor,the energy dissipated as heat equals the energy stored in the capacitor.