A bubble of air is underwater at temperature `15^(@)C` and the pressure `1.5` bar. If the bubble rises to the surface where the temperature is `25^(@)C` and the pressure is `1.0` bar, what will happen to the volume of the bubble?

Options

A. Volume will become smaller by a factor of 0.70
B. Volume will become greater by a factor of 2.5
C. Volume will become greater by a factor of 1.6
D. Volume will become greater by a factor of 1.1

Answer

C

Explanation

`(P_1V_1)/(T_1) = (P_2V_2)/(T_2)`
`(1.5 xx V)/(288) = (1 xx V_2)/(298)`
`V_2 = 1.55V` i.e., volume of bubble will be almost 1.6 time to initial volume of bubble.