Pressure remaining the same, the volume of a given mass of an ideal gas increases for every degree centigrade rise in temperature by define fraction of its volume at

Options

A. `0^@C`
B. Its critical temperature
C. Absolute zero
D. Its Boyle temperature

Answer

A

Explanation

`V_t = V_0 (1+ alpha_v t)`
`because (V_2 - V_1) = Delta V = V_0 alpha (t_2 - t_1)`
if `t_2 - t_1 = 1^@` then `Delta V = alpha V_0`
For every `1^@C` increase in temperature, the volume of a given mass of an ideal gas increases by a definite fraction `(1)/(273.15)` of `V_0` . Here `V_0` is volume at `0^@C` temperature.