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A specific volume of H2 requires 24 s to...

A specific volume of `H_2` requires 24 s to diffuse out of a container. The time required by an equal volume of `O_2` to diffuse out under identical conditions, is

A

24s

B

96s

C

384s

D

192s

Text Solution

Verified by Experts

The correct Answer is:
B
`(r_(O_2))/(r_(H_2)) = sqrt( (M_(H_2))/(M_(O_2)) )`
`(r_(O_2))/(r_(H_2)) = sqrt(2/32) = 1/4`
At time required by `H_2` is 24 s to diffuse out therefore `O_2` required s 96 to diffuse out.
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