What is the pressure of 2 mole of `NH_(3)` at `27^(@)C` when its volume is 5 lit. in Van der Waal's equation ? `(a = 4.17, b = 0.03711)`

Options

A. 10.33 atm
B. 9.33 atm
C. 9.74 atm
D. 9.2 atm

Answer

B

Explanation

`(P + (n^2a)/(V^2) ) (V - nb) = nRT`
`(P + ((2)^2 xx 4.17 )/((5)^2) )(5 - 2 xx .03711) = 2 xx .0821 xx 300`
`P = ( 2 xx .0821 xx 300)/(5 - 2 xx .03711) - (4.17 xx 2^2)/(5^2) rArr 10 - 0.66 = 9.33 atm`