The maximum number of molecules is present in

Options

A. 0.5g of `H_2` gas
B. 10g of `O_2` gas
C. 15L of `H_2` gas at STP
D. 5L of `N_2` gas at STP

Answer

C

Explanation

In 22.4L of 2 H maximum number of molecules ` = 6.022 xx 10^23`
In 1L of `H_2` maximum number of molecules
` = (6.022 xx 10^23)/(22.4)`
In 15L of `H_2` maximum number of molecules ` = (6.022 xx 10^23)/(22.4) xx 15 = 4.03 xx 10^23` molecules