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A certain gas takes three times as long ...

A certain gas takes three times as long to effuse out as helium. Its molar mass will be

A

27u

B

36u

C

64u

D

9u

Text Solution

Verified by Experts

The correct Answer is:
B
`r prop sqrt(1/M)`
`r_1/r_2 = sqrt(M_2/M_1)`
`((V_g)/(3t))/( (V_(He) )/(t) ) = sqrt(4/M)`
`1/9 = 4/M`
`M = 36g`/mole
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