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For the reaction CH(3)COOH(l)+2O(2)(...

For the reaction
`CH_(3)COOH(l)+2O_(2)(g)iff2CO_(2)(g)+2H_(2)O(l)" at "25^(@)C` and 1 atm. Pressure, `DeltaH=-874 kJ`. Then the change in internal energy `(DeltaE)` is ….

A

`-874 kJ`

B

`-871.53 kJ`

C

`-876.47 kJ`

D

`+874kJ`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta n_(g)=2 ("from " CO_(2))-2 ("form " O_(2))= 0`
So work done W= 0
Thus `Delta E= Delta H= -874kJ`
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