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Work done during isothermal expansion of...

Work done during isothermal expansion of one mole of an ideal gas form 10atm to 1atm at 300K is (Gas constant=`2`)

A

4938.8J

B

4138.8 J

C

5744.1 J

D

6257.2 J

Text Solution

Verified by Experts

The correct Answer is:
C
Given that `P_(1 )`= 10 atm, `P_(2) = 1` atm, T = 300K, n=1
R=8.314J/K/mol
Now, by using
`W =-2.303nRT "log"_(10) (p_(2))/(p_(1))`
`= -2.303 xx 1 xx 8.314 xx 300 "log"_(10) (1)/(10)`
`W= 5744.1` Joule
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