In an isobaric process, the ratio of heat supplied to the system `(dQ)` and work done by the system `(dW)` for diatomic gas is

Options

A. `1:1`
B. `7:2`
C. `7:5`
D. `5:7`

Answer

B

Explanation

`-(dQ)/(dW) = (dQ)/(dQ- dE), dE= dW + dQ, -dW= dQ- dE= (nc_(p) dT)/(nc_(p) dT- nc_(v) dT)= (c_(p))/((c_(p)- c_(v))) = (7R)/(2R)` {for diatomic of gas `c_(p)= (7R)/(2)`}