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For a carnot engine, the source is at 50...

For a carnot engine, the source is at 500 K and the sink at 300 K. What is efficiency of this engine

A

`0.2`

B

`0.4`

C

`0.6`

D

`0.3`

Text Solution

Verified by Experts

The correct Answer is:
B
Given that, `T_(1) = 500K, T_(2)= 300K`
By using, `eta= (T_(1)-T_(2))/(T_(1))= (500-300)/(500) = (200)/(500)= 0.4`
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