Home
Class 11
CHEMISTRY
When you freeze water in your freezer to...

When you freeze water in your freezer to make ice cubes,the amount of order in the molecules ofwater increases. However , second law of thermodynamics says that the amount of order in the isolated system can only stay constant or decrease with time. How can thus making of ice violate second law ?

A

Because water expands during ice formation

B

Because ice formation takes place at `0^(@)C`

C

Because ice is solid

D

Because ice cubes do not constitute isolated system

Text Solution

Verified by Experts

The correct Answer is:
D
Ice cubes are in contact with freezer so it does not constitute isolated system.
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS AND THERMOCHEMISTRY

    ERRORLESS|Exercise NCERT Based Questions (Heat of Reaction)|67 Videos

  • THERMODYNAMICS AND THERMOCHEMISTRY

    ERRORLESS|Exercise NCERT Based Questions (Bond Energy)|15 Videos

  • THERMODYNAMICS AND THERMOCHEMISTRY

    ERRORLESS|Exercise NCERT Based Questions (First Law of Thermodynamics and Hess Law)|55 Videos

  • THE S-BLOCK ELEMENTS

    ERRORLESS|Exercise Assertion & Reason|10 Videos

Similar Questions

Explore conceptually related problems

Read the passage carefully and answer the question given below: Massive kind of cyber security breaches that shattered some top enterprises has raised the topic of cyber security to the forefront. Though only large companies find their way to the headlines, small businesses are not free from several cyber security threats. The horrible fact remains that the impact of cyber-attack on a small business can often be devastating. Studies by National Cyber Security Alliance show that within six months of being hacked, over 60 percent of businesses have quit the scene once for all. The most common practices to combat cyber security issues are to deploy powerful antivirus software and also to backup the data on a regular basis. This is the first step any small business can take. However, there is still a lot more to stay protected at a time when the hackers have grown technologically advanced to challenge any kind of proactive measure. Those enterprises creating easy and simple passwords like ABCD or 1234 are only facilitating a cake walk for the hackers to crack their system code. Experts advise to put some innovation in passwords including numerals, characters and alphabets. Tough passwords make it tough for hackers to crack them. Time and again remind your employees to create new and strong passwords and also change them often. Keep password attempts to minimum Most hackers try random passwords till they are able to open your account successfully. If you have implemented a six-digit pin, you are only creating a million unique possibilities and so your account is never safe. Today there are amazing passwords cracking software that can easily guess your codes within a few minutes. Therefore, keep the password attempts to minimum during every stage of the authentication process. Password management tools help create strong passwords and also remember them. So, many business wish to install them for their many advantages. However, the big downside to them is the passwords are stored in their databases making it handy for the hackers to get all of them if they can access the location just once. So, ascertion the password management tool you are depending on is reliable. Question: According to the passage, how devastating can cyber-attacks get on small firms ?

Free enegry , G = H - TS , is state function that indicates whther a reaction is spontaneous or non-spontaneous. If you think of TS as the part of the system's enegry that is disordered already, then (H -TS) is the part of the system's energy that is still ordered and therefore free to cause spontaneous change by becoming disordered. Also, DeltaG = DeltaH - T DeltaS From the second law of thermodynamics, a reaction is spontaneous if Delta_("total")S is positive, non-spontaneous if Delta_("total")S is negative, and at equilibrium if Delta_('total")S is zero. Since, -T DeltaS = DeltaG and since DeltaG and DeltaS have opposite sings, we can restate the thermodynamic criterion for the spontaneity of a reaction carried out a constant temperature and pressure. IF DeltaG lt 0 , the reaction is spontaneous. If DeltaG gt 0 , the reaction is non-spontaneous. If DeltaG = 0 , the reaction is at equilibrium. Read the above paragraph carefully and answer the following questions based on the above comprehension. For the spontaneity of a reaction, which statement is true?

ERRORLESS-THERMODYNAMICS AND THERMOCHEMISTRY-NCERT Based Questions (IInd & IIIrd Law of Thermodynamics and Entropy)
  1. An engine operating between 150^(@)C and 25^(@)C takes 500 J heat from...

    Text Solution

    |

  2. For a carnot engine, the source is at 500 K and the sink at 300 K. Wha...

    Text Solution

    |

  3. When you freeze water in your freezer to make ice cubes,the amount of ...

    Text Solution

    |

  4. Given the following entropy values (in JK^(-1)"mol"^(-1)) at 298 K atm...

    Text Solution

    |

  5. Choose the reaction with negative DeltaS value

    Text Solution

    |

  6. Which of the following is correct for adiabatic expansion ideal gas?

    Text Solution

    |

  7. 9.0 g of H2 O is vaporized at 100^@C and 1 atm pressure. If the latent...

    Text Solution

    |

  8. If the enthalpy of vaporisation of water is 186.5 J mol^(-1), then ent...

    Text Solution

    |

  9. Which of the following statements is true? The entropy of the universe

    Text Solution

    |

  10. Which of the following is correct

    Text Solution

    |

  11. Identify the correct statement regarding entropy

    Text Solution

    |

  12. Entropy change involve in conversation of 1mole of liquid water at 373...

    Text Solution

    |

  13. Entropy will not change for the reaction

    Text Solution

    |

  14. The unit of entropy is

    Text Solution

    |

  15. underset(S^(@)(298K)K^(-1)mol^(-1))(H^(+)(aq))+underset(-10.7)(OH^(-)(...

    Text Solution

    |

  16. Which is the correct expression that relates changes of entropy with t...

    Text Solution

    |

  17. One mole of which of the following has the highest entropy

    Text Solution

    |

  18. Predict the sign of DeltaS^(@) for the following reaction : 2H(2)S (...

    Text Solution

    |

  19. Enthalpy of vapourization of benzene is +35.3 kJ mol^(-1) at its boili...

    Text Solution

    |

  20. Entropy change in a process where 1 litre of liquid He is poured into ...

    Text Solution

    |