An irreversible process occurring isothermally in an isolated system leads to

Options

A. Zero entropy
B. An increase in the total entropy of the system
C. A decrease in the total entropy of the system
D. None of these

Explanation

To solve the question regarding the entropy changes during an irreversible process occurring isothermally in an isolated system, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concepts**:
- An **isolated system** is one that does not exchange heat or matter with its surroundings.
- An **isothermal process** is one that occurs at a constant temperature.
- **Entropy** is a measure of the disorder or randomness in a system.

2. **Recall the Second Law of Thermodynamics**:
- The second law states that the total entropy of an isolated system can never decrease over time. For any spontaneous (irreversible) process, the total entropy of the system and its surroundings must increase.

3. **Analyze the Irreversible Process**:
- In an irreversible process, the entropy of the system will increase. This is because irreversible processes lead to a greater degree of disorder compared to reversible processes, where the entropy change can be zero.

4. **Consider the Isothermal Condition**:
- Since the process is isothermal, the temperature remains constant, but this does not affect the increase in entropy due to irreversibility.

5. **Conclusion**:
- Therefore, during an irreversible process occurring isothermally in an isolated system, the total entropy of the system will **increase**.

### Final Answer:
The correct option is that an irreversible process occurring isothermally in an isolated system leads to an **increase in the total entropy of the system**.

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