If `S+O_(2)toSO_(2),DeltaH=-298.2 " kJ" " mole"^(-1)`
`SO_(2)+(1)/(2)O_(2)toSO_(3)DeltaH=-98.7 " kJ" " mole"^(-1)`
`SO_(3)+H_(2)OtoH_(2)SO_(4),DeltaH=-130.2 " kJ" " mole"^(-1)`
`H_(2)+(1)/(2)O_(2)toH_(2)SO_(4),DeltaH=-287.3 " kJ" " mole"^(-1)`
the enthlapy of formation of `H_(2)SO_(4)` at 298 K will be

Options

A. `-433.7 kJ`
B. `-650.3 kJ`
C. `+320.5 kJ`
D. `-813.9kJ`

Answer

D

Explanation

`S + O_(2) rarr SO_(2), Delta H= -298.2`
`SO_(2) + (1)/(2) O_(2) rarr SO_(3) , Delta H= - 98.2`
`SO_(3) + H_(2)O rarr H_(2)SO_(4), Delta H= -130.2`
`H_(2) + (1)/(2) O_(2) rarr H_(2)O, Delta H= -287.3`
On adding all the equations
`S + 2O_(2) + H_(2) rarr H_(2)SO_(4), Delta H= -813.9 kJ`