When 5 g of sulphur is burnt to `SO_(2)`, 46 kJ of heat is liberated. What is the enthalpy of formation of sulphur dioxide?

Options

A. `+ 147.2` kJ
B. `-147.2` kJ
C. `-294.4` kJ
D. `+ 294.4` kJ

Answer

C

Explanation

`S + O_(2) rarr SO_(2), Delta H_(f)= -4.6 kJ`
`because 0.5g` of sulphur on burning produce 1g of `SO_(2)`
`therefore` 32g of sulphur on burning produce 64g of `SO_(2)`
`Delta Delta H= (-4.6kJ) xx 64 = -294.4kJ`