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Standard enthalpy of vaporisationDeltaV(...

Standard enthalpy of vaporisation`DeltaV_(vap).H^(Theta)` for water at `100^(@)C`is`40.66kJmol^(-1)`.The internal energy of Vaporization of water at` 100^(@)C("in kJ mol"^(-1))`is

A

`+ 37.56`

B

`-43.76`

C

`+ 43.76`

D

`+ 40.66`

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta H= Delta E + Delta n_(g) RT`
`40.66 xx 1000= Delta E + (1) xx 8.314 xx 373)`
`Delta E= 37.56` kJ `mol^(-1)`
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