The standard enthalpy or the decomposition of `N_2 O_5 `to `NO_2` is 58.04 kJ and standard entropy of this reaction is 176.7 J/K. The standard free energy change for this reaction at `25^@`C is_____________.

Options

A. 539 kJ
B. `-539` kJ
C. `-5.39` kJ
D. 5.39 kJ

Answer

D

Explanation

`Delta H^(@)= 58.04kJ, Delta S^(@)= 176.7 xx 10^(-3)` kJ/K
`T^(@) = 25^(@) C = 298K`
`Delta G = Delta H^(@)- T^(@) Delta S^(@)`
`=58.04 - 298 xx 176.7 xx 10^(-3)`
=5.39kJ