The correct thermodynamic conditions for the spontaneous reaction at all temperatures is

Options

A. `Delta H lt 0 and Delta S= 0`
B. `Delta H gt 0 and Delta S lt 0`
C. `Delta H lt 0 and Delta S gt 0`
D. `Delta H lt 0 and Delta S lt 0`

Answer

C

Explanation

`Delta G= Delta H- T. Delta S`
For, `Delta H lt 0 and Delta S gt 0, Delta G= -ve` (always)
`therefore` spontaneous at all temperature