56 g of nitrogen and 8 g hydrogen gas are heated in a closed vessel. At equilibrium 34 g of ammnia are present. The equilibrium number of moles of nitrogen, hdregen and ammonia are respectively

Options

A. `1,2,2`
B. `2,2,1 `
C. `1,1,2 `
D. `2,1,2 `

Answer

C

Explanation

`N_2 +3H_2 hArr 2NH_3 " ".....(i)`
at `{:(t= 0 ,56 g, 8g ,0g),(=,2 "mole",4"mole",0"mole"):}`
at equilibrium 2 -1 4 - 3 `" "` 34g
=1mole = 1mole = 2mole
According to eq. (i) 2 mole of ammonia are present & to produce 2 mole of `NH_3` , we need 1 mole of `N_2` and 3 mole of `H_2` hence 2 - 1 = 1 mole of `N_2 and 4 = 3 = 1` mole of `H_2` are present at equilibrium in vessel.