`XY_(2)` dissociates `XY_(2)(g) hArr XY(g)+Y(g)`. When the initial pressure of `XY_(2)` is `600` mm Hg, the total equilibrium pressure is `800` mm Hg. Calculate K for the reaction Assuming that the volume of the system remains unchanged.

Options

A. 50
B. `100.0`
C. 166.6
D. `400.0`

Answer

B

Explanation

`XY_2 hArr XY +Y`
Initial pressure of ` XY_2 600` mmHg
According to equation,
`XY_2 hArr XY +Y`
`{:("Initial", 600, 0 ,0),("At equilibrium", 600 – P, P, P):}`
Total = 600 + P = 800
P = 200
`K= (200 xx 200)/400 = 100.0`