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K(p) and K(p)^(**) are the equilibrium c...

`K_(p) and K_(p)^(**)` are the equilibrium constants of the two reactions, given below
`(1)/(2)N_(2)(g)+(3)/(2)H_(2)(g)hArr NH_(3)(g)`
`N_(2)(g)+3H_(2)(g)hArr 2NH_(3)(g)`
Therefore, `K_(p) and K_(p)^(**)` are related by

A

`K_p =K'_(p)^(2)`

B

`K_p=sqrt(K'_p)`

C

`K_p =2K'_(p)`

D

`K_p=K'_p`

Text Solution

Verified by Experts

The correct Answer is:
B
When a balanced equation having equilibrium constant Kp is multiplied by a certain value n, the equilibrium constant for the new equation will be equal to n `(K_p)^n`
In the given equation, n = 2
So, `K._p=(K_p)^2 " or " K_p =sqrt(K._p)`
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