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For the reaction, 2NO(2)(g) rarr 2NO(g) ...

For the reaction, `2NO_(2)(g) rarr 2NO(g) + O_(2)(g), K_(c) = 1.8 xx 10^(-6) "at" 185^(@)C`, the value of `K_(c)` for the reaction `NO(g) + 1/2O_(2)(g) rarr NO_(2)(g)` is

A

`0.9xx10^6`

B

`7.5xx10^2`

C

`1.95xx10^(-3)`

D

`1.95xx10^(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
Reaction is reversed and halved.
`K=sqrt(1//1.8 xx10^(-6))=7.5 xx10^2`
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