One mole of a compound AB reacts with 1 mole of a compound CD according to the equation `AB + CD hArr AD + CB`.
When equilibrium had been established it was found that `(3)/(4)` mole each of reactant AB and CD has been converted to AD and CB. There is no change in volume. The equilibrium constant for the reaction is

Options

A. `9/16`
B. `1/9`
C. `16/9`
D. 9

Answer

D

Explanation

`AB + CD hArr AD + CB`
`{:("Mole at t = 0", 1, 1, 0, 0),("Mole at equilibrium",(1-3/4),(1-3/4),(3/4),(3/4)),(,0.25,0.25,0.75,0.75):}`
`K_c=(0.75 xx0.75)/(0.25 xx0.25)=(0.5625)/(0.0625)=9`