For the reaction `C(s) +CO_(2)(g) rarr 2CO(g), k_(p)=63` atm at 100 K. If at equilibrium `p_(CO)=10p_(CO_(2)) ` then the total pressure of the gases at equilibrium is

Options

A. 6.3 atm
B. 6.93 atm
C. 0.63 atm
D. 0.693 atm

Answer

B

Explanation

`C_((s)) + CO_(2(g)) rarr 2CO_((g))`
Apply law of mass action,
`K_p =((P_(CO))^2)/(P_(CO_2))" or " 63= (10(P_(CO_2))^2)/(P_(CO_2))`
or 63 or ` 63= (10(P_(CO_2))^2)/(P_(CO_2))" or " 63 =100 P_(CO_2)`
`P_(CO_2)=63/100 =0.63 atm`
`P_(CO)=10P_(CO_2)=10xx0.63 =6.3` atm
`P_("Total") = P_(CO_2) +P_(CO) = 0.63 + 6.3 = 6.93` atm.