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A + B hArrC + D. Initially the concentra...

`A + B hArrC + D`. Initially the concentrations of `A` and `B` are both equal but at equilibrium, concentration of `C` will be twice of that of `A` then what will be the equilibrium constant of reaction.

A

4

B

2

C

`1//4`

D

`1//2`

Text Solution

Verified by Experts

The correct Answer is:
A
`A+B hArr C+D`
`{:("At equilibrium ",a ,a ,2a ,2a):}`
`K = (2a xx2a)/(axxa) =4`
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