Formaldehyde polymerizes to form glucose according to the reaction, `6HCHO rarr C_(6)H_(12)O_(6)` The theoretically computed equilibrium constant for this reaction is found to be `6 xx 10^(22)` If 1M solution of glucose dissociates according to the above equilibrium, the concentration of formaldehyde in the solution will be :

Options

A. `1.6xx10^(-8)M`
B. `3.2xx 10^(-6)M`
C. `3.2xx 10^(-4)M`
D. `1.6xx10^(-4)M`

Answer

D

Explanation

`6HCHO hArr C_(6)H_(12)O_6 K = 6 xx10^(22)`
`C_(6)H_(12)O_6 hArr 6HCHO " "K. =1/(6 xx10^(22))`
`1-x " " 6x " "` at equilibrium
`K.=((6x)^6)/(1-x) =1/(6xx10^(22))`
`((6x)^6)/(1) =16.67xx10^(-24) " " [1-x~~1]`
`6x= (16.67)^(1//6) xx(10^(-24))^(1//6)`
`6x = 1.6 xx10^(-4)`