3 moles of A and 4 moles of B are mixed together and allowed to come into equilibrium according to the following reaction
`A(g) + 4 B(g) hArr 2 C (g) + 3 D (g)`
When equilirium is reached , there is 1 mole of C. The equilibrium extent of the reaction is

Options

A. `1/4`
B. `1/3`
C. `1/2`
D. 1

Answer

C

Explanation

`3A +4B hArr 2C +3D`
`implies K_1 = ([C]^2[D]^3)/([A]^3[B]^4)" "...(i)`
When moles of C = 1, the equation becomes
`3/2 A +2B hArr C+(3)/2 D`
`implies K_2 = ([C][D]^(3//2))/([A]^(3//2)[B]^2)" "...(ii)`
On comparing Eq. (i) with Eq. (ii), we get
`K_2^2 = K_(1)` or `K_2 =(K_1)^(1//2)`
Hence, equilibrium extent `=1/2`